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Home » Black Corset Carnage: The Bold Look Everyone’s Obsessed With Right Now! - American Beagle Club

Black Corset Carnage: The Bold Look Everyone’s Obsessed With Right Now! - American Beagle Club

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 Set to zero: \(1 = rac{8}{t^3} \Rightarrow t^3 = 8 \Rightarrow t = 2\), not in domain. So maximum occurs at endpoint \(t = 1\)

📌 Then \(f(1) = 1 + 1 + 4 = 6\)

📌 As \(t o 0^+\), \(f(t) o \infty\), but wait â is \(t\) bounded below? Yes, but \(rac{4}{t^2} o \infty\), so function has no maximum?

📌 But in domain \(0 < x < \pi/2\), \(\sin 2x = 0\) is not attained, but approaches 0, so \(rac{4}{\sin^2 2x} o \infty\), so expression tends to infinity?

📌 But question says "find the maximum", implying it exists. Contradiction?

📌 Wait â at \(x = \pi/4\), \(\sin 2x = 1\), \(f = 1 + 1 + 4 = 6\), value 6.

📌 But for small \(x\), say \(x = 0.1\), \(\sin 2x pprox 0.1987\), \(rac{4}{t^2} pprox 101.3\), so \(f pprox 1 + 0.1987 + 101.3 pprox 102.4 > 6\)

📌 So function increases without bound? But at \(x o 0^+\), \(\sin x o 0\), \(\cos x o 1\), \( an x o 0\), \(\cot x o \infty\), so \(( an x + \cot x)^2 o \infty\)

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