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\(\boxed\textThere is no horizontal asymptote.\) - American Beagle Club

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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Set \( C(t) = 10t e^{-0.1t} \), then \( C' = 10e^{-0.1t}(1 - 0.1t) \),...
e^{-0.1t}(1 - 0.1t) = 0.1
Try t=2: \( e^{-0.2} \approx 0.8187 \), \( 1 - 0.2 = 0.8 \), product ≈...
t=5: \( e^{-0.5} \approx 0.6065 \), \( 1 - 0.5 = 0.5 \), product ≈ 0.3...
t=10: \( e^{-1} \approx 0.3679 \), \( 1 - 1 = 0 \), product = 0
Perhaps stick to original derivation and assume the intended answer is...
Alternatively, re-solve with correct math:
We have:
\frac{10}{(t+2)^2} = -
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