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Home » From Obscurity to Legend: The Fascinating Journey of Wallace Scott pilgrim! - American Beagle Club

From Obscurity to Legend: The Fascinating Journey of Wallace Scott pilgrim! - American Beagle Club

📅 February 28, 2026 👤 scraface

Feb 28, 2026

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Solution: Let $ S = rac{a + b}{a - b} + rac{a - b}{a + b} $. Combine...
S = rac{(a + b)^2 + (a - b)^2}{(a - b)(a + b)} = rac{2a^2 + 2b^2}{a^...
Since $ |a| = |b| = 1 $, $ a \overline{a} = 1 $ and $ b \overline{b} =...
S + \overline{S} = rac{(a + b)^2 + (a - b)^2}{a^2 - b^2} = rac{2a^2...
But $ a
eq b $, and $ |a| = |b| = 1 $. Let $ b = \overline{a} $ (since $ |a| =...
eq \overline{a} $ unless $ a $ is real, which contradicts $ a
eq b $. Instead, note that $ rac{a + b}{a - b} + rac{a - b}{a + b} =...
S = rac{2(e^{i heta} + e^{-i heta} + e^{i\phi} + e^{-i\phi})}{e^{i he...
This simplifies to $ rac{2(2\cos heta + 2\cos\phi)}{2i(\sin heta - \s...

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