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Home » From Shock to Awe: The Powerful Story Behind Reef Cora That’s Going Viral! - American Beagle Club

From Shock to Awe: The Powerful Story Behind Reef Cora That’s Going Viral! - American Beagle Club

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 Solution: We are given 5 distinct parts: A, B, C, D, and E, and we are to count the number of permutations where A appears before B and C appears before D.

📌 First, the total number of permutations of 5 distinct parts is $5! = 120$.

📌 In any random permutation, the relative order of A and B is equally likely to be A before B or B before A. So, exactly half of the permutations have A before B. Similarly, exactly half have C before D.

📌 These two events (A before B and C before D) are independent, because the positions of A and B do not affect the relative order of C and D (since all parts are distinct and no further constraints are linked).

📌 Therefore, the number of permutations satisfying both conditions is:

📌 \frac{1}{2} \times \frac{1}{2} \times 5! = \frac{1}{4} \times 120 = 30

📌 Thus, the robot can produce $\boxed{30}$ valid sequences.

📌 Question: A virologist is analyzing a synthetic virus with a genome composed of 8 nucleotide segments, each of which can be one of four types: A, U, C, or G. She is particularly interested in configurations where exactly 3 segments are adenine (A), and no two adenine segments are adjacent. How many such valid genome sequences are possible?

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