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Home » If \(n+1\) is even, then \(n+1\) is divisible by 2. - American Beagle Club

If \(n+1\) is even, then \(n+1\) is divisible by 2. - American Beagle Club

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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\[ 3k + 2k = 5k = -b \]
\[ b = -5k \]
\[ (3k)(2k) = 6k^2 = c \]
We need values for \( b \) and \( c \) in terms of \( k \). To find \(...
From \( b = -5k \), we have \( k = -\frac{b}{5} \).
Substitute into the expression for \( c \):
\[ c = 6\left(-\frac{b}{5}\right)^2 = 6 \cdot \frac{b^2}{25} = \frac{6...
Thus, the values of \( b \) and \( c \) in terms of the ratio are:
\[ b = -5k, \quad c = 6k^2 \]
Given the ratio, if \( b = -5 \), then \( k = 1 \) and \( c = 6 \). Th...

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