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Target Affiliate Program: Unlock 50% Monthly Bonuses You Can’t Ignore! - American Beagle Club

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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b = \sqrt{c^2 - a^2} = \sqrt{100 - 36} = \sqrt{64} = 8 \text{ cm}
Area of the triangle:
A = \frac{1}{2} \cdot 6 \cdot 8 = 24 \text{ cm}^2
The altitudes corresponding to each side are found using \(A = \frac{1...
Altitude to leg \(a = 6\):
h_a = \frac{2A}{6} = \frac{48}{6} = 8 \text{ cm}
Altitude to leg \(b = 8\):
h_b = \frac{2A}{8} = \frac{48}{8} = 6 \text{ cm}
Altitude to hypotenuse \(c = 10\):
h_c = \frac{2A}{10} = \frac{48}{10} = 4.8 \text{ cm}

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\boxed{18\pi}
Question:** An electrical engineer studies a alternating current signa...
First, express \( z(t) \) in terms of cosine and sine:
z(t) = 4(\cos \omega t + i\sin \omega t) + 3(\cos \omega t - i\sin \om...
z(t) = 7\cos \omega t + i\sin \omega t
Now compute the magnitude:
|z(t)| = \sqrt{(7\cos \omega t)^2 + (\sin \omega t)^2} = \sqrt{49\cos^...
= \sqrt{48\cos^2 \omega t + (\cos^2 \omega t + \sin^2 \omega t)} = \sq...
The maximum occurs when \( \cos^2 \omega t = 1 \):
|z(t)|_{\text{max}} = \sqrt{48 + 1} = \sqrt{49} = 7

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