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Home » The #1 MLG Review That’s Dominating Online Chats Right Now! - American Beagle Club

The #1 MLG Review That’s Dominating Online Chats Right Now! - American Beagle Club

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 To find \( t \), we solve the equation \( 3t + 4 = 19 \).

📌 Now substitute \( t = 5 \) into \( 2t + 3 \):

📌 2(5) + 3 = 10 + 3 = 13

📌 Thus, the value is \(\boxed{13}\).

📌 Question: A theoretical physicist models a quantum state where the sum of two energy levels \( E_1 \) and \( E_2 \) is 12 units, and \( E_1^2 + E_2^2 = 80 \). Find \( E_1^3 + E_2^3 \).

📌 E_1 + E_2 = 12, \quad E_1^2 + E_2^2 = 80

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Substitute into first: \( 2(3) + 3y = 12 \) → \( 6 + 3y = 12 \) → \( 3...
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From \( b = -5k \), we have \( k = -\frac{b}{5} \).
Substitute into the expression for \( c \):
\[ c = 6\left(-\frac{b}{5}\right)^2 = 6 \cdot \frac{b^2}{25} = \frac{6...
Thus, the values of \( b \) and \( c \) in terms of the ratio are:
\[ b = -5k, \quad c = 6k^2 \]
Given the ratio, if \( b = -5 \), then \( k = 1 \) and \( c = 6 \). Th...
\(\boxed{b = -5, \, c = 6}\)
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\[ G(t) = \frac{3t^2 + 2t + 1}{t + 1} \]
Find the horizontal asymptote of this function as \( t \to \infty \).

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