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Home » We must count all 3-tributary selections satisfying this rule. - American Beagle Club

We must count all 3-tributary selections satisfying this rule. - American Beagle Club

📅 February 26, 2026 👤 scraface

Feb 26, 2026

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Total colonies = 1,248 + 1,576 + 987 = <<1248+1576+987=3811>>3,811
Dormant colonies = 18% of 3,811 = 0.18 × 3,811 = <<0.18*3811=685.98>>6...
Active colonies = 3,811 − 686 = <<3811-686=3125>>3,125
Dr. Vance models the growth of a deep-sea extremophile using the funct...
\( N(6) = 500 \cdot e^{0.3 \cdot 6} = 500 \cdot e^{1.8} \)
Using \( e^{1.8} \approx 6.0496 \), we get:
\( 500 \cdot 6.0496 = <<500*6.0496=3024.8>>3024.8 \)
Rounded = <<round(3024.8)=3025>>3,025

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