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"You Won’t BELIEVE What Dsgss Does—90% of Users Are Obsessed! - American Beagle Club

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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Solution: We aim to minimize:
|2\sin x + 3\cos x + 4|
First, consider the expression inside the absolute value: $ 2\sin x +...
2\sin x + 3\cos x = R\sin(x + \phi)
where $ R = \sqrt{2^2 + 3^2} = \sqrt{4 + 9} = \sqrt{13} $.
2\sin x + 3\cos x = \sqrt{13} \sin(x + \phi)
The range of $ \sqrt{13} \sin(x + \phi) $ is $ [-\sqrt{13}, \sqrt{13}]...
2\sin x + 3\cos x + 4 \in [4 - \sqrt{13}, 4 + \sqrt{13}]
Since $ \sqrt{13} \approx 3.605 $, $ 4 - \sqrt{13} \approx 0.395 > 0 $...
Therefore, the absolute value $ |2\sin x + 3\cos x + 4| $ achieves its...

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