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Home » YouTube TV Price Increase Exposed: Did You Get Ripped Off? - American Beagle Club

YouTube TV Price Increase Exposed: Did You Get Ripped Off? - American Beagle Club

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 Thus, \( d \) must be a divisor of 144, and \( m + n = \frac{144}{d} \). Since \( m \) and \( n \) are coprime positive integers, \( m + n \geq 2 \), so \( \frac{144}{d} \geq 2 \Rightarrow d \leq 72 \).

📌 To maximize \( d \), we take the largest divisor of 144 such that \( \frac{144}{d} \geq 2 \) and there exist coprime \( m, n \) with \( m + n = \frac{144}{d} \).

📌 The largest divisor of 144 is 144 itself, but then \( m + n = 1 \), impossible. Next, try \( d = 72 \): then \( m + n = 2 \), so \( m = n = 1 \), which are coprime. Then \( a = 72 \), \( b = 72 \), and \( \gcd(72, 72) = 72 \). Valid.

📌 So the maximum possible \( \gcd(a, b) \) is:

📌 \boxed{72}

📌 A hydrologist models contaminant dispersion in groundwater using modular arithmetic, where the signal strength at time step \( t \) modulo 9 determines flow stability. What is the remainder when the sum \( 1^3 + 2^3 + 3^3 + \dots + 9^3 \) is divided by 9?

📌 We compute $ S = \sum_{k=1}^{9} k^3 \mod 9 $.

📌 Use the formula for the sum of cubes:

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